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1. Sep 25, 2005 at 10:43 AM #31
   

   [A]uthority Well-Known Member

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   ? You can't do this? These are the easiest math questions I ever seen. But probably your in like 7th grade or somethin, dunno.

    
2. Sep 25, 2005 at 3:25 PM #32
   

   stott Well-Known Member

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   that's not a hard problem.
   
   [(x-3)(x-1)]/[(x-4)(x-3)]
   
   (x-3) will cancel, giving you a hole at x = 3, and so the limit as x approaches 3 equals -2

    

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