Logarithms (algebra 2) Pay: 1,000 Credits

Okay, I have 3 pages due by Tuesday (really Wednesday, but I figure the earlier the better. ) I'm only requiring the person who takes this up to do one page and to teach me how to do 3 different problems (which I will list later) step by step. The pay is 1,000 credits.

The reason I want you to teach me is because I've been absent ALOT during this past semester, and I never had a chance to learn it.

Here's the page:

AND I want to know how to do one of the problems above, and the following:

log₅x = 2log₅10

&

10^x = 923

MONDAY NIGHT if possible (Will be up until at least 1 am tue morning, and will wake at 7, but I want to at least have a chance to complete the other two assignments.)

 

i actually failed this section last month, good luck.

 

Do you have a calcualtor? If so, it is quite easy. You'll just need to learn the concepts.

 

yah almost all of this can be done on a calculator

 

Yup, actually, I do have a calculator.

 

log5x = 2log510 Isn't this one just

log5x = 2log510 -log5
x = log510 -10
x-10=log5

Not sure..

 

1. 9
2. 32 = 4^x
3. 32 = 9^x
4. 2
5. 4
6. 1/25
7. 0
8. 1/9

etc.......

If you need help just find me on aim one time or something and I'll help u for free

AIM = skilledplayer69

 

These are simple
using the logarithmic laws

I can teach you how to do this in seconds
My MSN is [email protected]
Contact me in about 20 minutes ... LUNCH time for me

Also I will post the answers here in 20 min

after lunch
-Z

 

I can also help you.

---

Here are the last 6 answers.

09) 1
10) 3
11) 8
12) -2
13) 81
14) 5

---

log(5)x = 2log(5)10

First find out what the right part is.
log(5)10= 1.43....
Do that *2 = 2.86...

And then
x = 5^2.86...
x= 100

---

10^x = 923
x = log(10)923
x = 2.9652......

 

Ok Back and here are the answers:

1. log₇7⁹ = x
x = 9
2. log₄32 = x
x = 2.5
3. log₉32 = x
x = 1.5773
4. log₄16 = x
x = 2
5. log_x4 = 1
x = 4
6. log₅X = -2
x = 1/25
7. log₃1 = x
x = 0
8. log_x81= -2
x = 1/9
9. log₃24 - log₃8 = x
x = 1
10. 2log₄8 = x
x = 3
11. log₆₄X = (1/2) <- one half. lol
x = 8
12. log₃(1/9) = x
x = -2
13. log_x9 = (1/2)
x = 81
14. log₁₀500 + log₁₀200 = x
x = 5

Also:
log₅x = 2log₅10
RHS: 2 * (log ₅ 10 )
= 2 * (1.43067)
= 2.86135
LHS: log ₅x = 2.86135
Meaning 5^2.86135 = X
X = 100

10[sup]x = 923
Meaning
Log (923) / Log (10) = x
x = 2.965201

Enjoy
-Zain

Edit: Whoops Looks like Quyxz got em

 

YAY right ftw!

 

I did Logs and Ln like 2 years ago
In HS

-Z

 

Never had this but thought my method was ok

 

Thanks and I love your avatar, rofl.

Thanks both of ya'll. To be honest, I want to give 1,000 to both of you but is it okay with ya'll if I give you 500 each? I'm pretty sure this is against the rules, but maybe I can pay ya'll the final 500 credits when I buy some more when I get my job? lol

 

These sare quite easy, once you know the laws they are cake.