Amen. In other words.. My Brain hurts.. And Math is the Devil.. The End. Just my two-cents on this subject.. [/b][/quote] Math does not suck balls. . .
Math does not suck balls. . . [/b][/quote] Ok fine.. It doesnt.. It just sucks everything.. Just playing.. I just hate Math.. Stresses me out like woah.. Yo..
I don't get it. How does .9999 repeating equal one? Some other dude explained it, but I don't get it. It's like, confusing.
Proof defined: The validation of a proposition by application of specified rules, as of induction or deduction, to assumptions, axioms, and sequentially derived conclusions. Okay so we are going to deduce a proof through sequentially derived conclusions. We can all agree that 1/9 equals .1 repeating (check it with a calculator). So, watch this... 1/9 = .1 repeating 2/9 = .2 repeating 3/9 = .3 repeating 4/9 = .4 repeating 5/9 = .5 repeating 6/9 = .6 repeating 7/9 = .7 repeating 8/9 = .8 repeating Check these in a calculator if you want... Here is where the proof kicks in... 9/9 = .9 repeating? But look at 9/9, isn' that equal to 1? Because any number over itself is equal to 1. Make sense?
ya 0.9 repeating doesnt equal 1 unless its rounded [/b][/quote] Yes it does. Ample proof has already been provided, so I suggest you read some of the posts.... Either way, here's proof that all women are evil <_<: Having a girl means investing time and money, right? So: Women = Time * Money And, we also know that "time is money," therefore: Time = Money Consequently, if we substitute into the first statement: Women = Money * Money = Money^2 Now, we also know that "money is the root of all evil," right? Therefore, Money = sqrt(Evil) If we substitute that into our newly derived women function, we get: Women = Money^2 = [sqrt(Evil)]^2 Obviously, the square root and square cancel each other out, thus leaving you with Women = Evil Irrefutable proof, ladies and gentlemen. And yeah, I know this is old. I'm just bored. <_<
Proof defined: The validation of a proposition by application of specified rules, as of induction or deduction, to assumptions, axioms, and sequentially derived conclusions. Okay so we are going to deduce a proof through sequentially derived conclusions. We can all agree that 1/9 equals .1 repeating (check it with a calculator). So, watch this... 1/9 = .1 repeating 2/9 = .2 repeating 3/9 = .3 repeating 4/9 = .4 repeating 5/9 = .5 repeating 6/9 = .6 repeating 7/9 = .7 repeating 8/9 = .8 repeating Check these in a calculator if you want... Here is where the proof kicks in... 9/9 = .9 repeating? But look at 9/9, isn' that equal to 1? Because any number over itself is equal to 1. Make sense? [/b][/quote] .99~ doesnt equal 1.... unless you round let me try to clear this up for all you confused people. the calculator is trickery. 1/3 is the decial equvalent to .33~ thats true,but it does not equal .33~ the number never ends thereby forcing a) you or b) the calculator to round up. so technically .999~ is not equal to one. but since it doesnt end, you do not know what it is equal to because you do not know the last number so you can round up at any point down the line.
wow, are you guys going to tell me that 0^0 doesn't =1 as well? look at it the way everyone shows it x=.9999999 <- you can have as many 9 as you want, it wont matter then you multiply it by ten 10x=9.999999 because .9999999 x 10 , just move the decimal over, but since it's a repeating decimal, all the 9's after the decimal do not change. then subtract x (x still = .9999999) so you get 9x = 9 (you just take off the infinite 9) divide both sides by 9, and you get x=1. the only proof you guys are offering, is if the decimal is non repeating. it's not an asymptote.
Actually, you have it backwards. The ONLY time when .33~ is equal to 1/3 is when you have an infinite amount of 3's after the decimal. At NO other point will that occur. .3 = 3/10 .33 = 33/100 .333 = 333/1000 .3333 = 3333/10000 .... you can keep going and you will NEVER get to 1/3, except for when you actually have an infinite amount of 3's, hence why 0.33~ = 1/3 Uhh...0^0 does NOT equal 1. Technically speaking, any number raised to the zeroth power is equal to 1, and 0 raised to any number is 0, EXCEPT when you have 0^0. That value itself is undefined...
lol, in the elementary shell i see.. raising a number to the power of 0 is 1. even 0, just because you have nothing to start with does not mean it does not go to 1. look at it this way.. 10^3=1000 10^2=100 10^1=10 10^0=1 10^-1=1/10 10^-2=1/100 10^-3=1/1000 the reason any number to the power of 0 is 1 is because powers go by places (you know, 1's place, 10's place 100's place, like those colored cubes from elementary school) 0 is the reperesentation for the 1's place. it's common knowledge that everything times 0 = 0, and everything to the 0 power is 1. 0^0 *does* in fact, = 1
You obviously know nothing. If you have a graphing calculator, plug it in and see. If you have a graphing calculator, plot the equation y = x^0 and tell me what you get. I guarantee you'll get a straight line where y = 1, and you'll have a HOLE where x = 0. You don't have to believe me, kiddo, try it out yourself. Either way, going back to what the other dude said: I came up with the proof on why .33~ is equal to 1/3...Here it is: Consider this summation, which we'll call x: x = 3 * (10^(-n)) where n is any integer from 1 to infinity. This basically gives you 0.333~ because you have x = 3*1/10 + 3*1/100 + 3*1/1000 + ... + 3 * (10^(-n-1)) + 3 * (10^(-n)) Now, suppose that you have the same summation, but this time multiplied by 10 (aka 10x), therefore leaving you with: 10x = 3*10*10^(-n), or in other words, 10x = 3*10^(1-n), where n is any integer from 1 to infinity Therefore, your values look like this on the second summation: 3*1 + 3*1/10 + 3*1/100... + 3*10^(-n) + 3*10^(1-n) Now, if you subtract this second summation from the first one (x-10x), you get every term cancels out with each other except for the first and last terms in the second summation, that is x - 10x = -3 - 3*10^(1-n) Simplifying, you have -9x = -3 (1+10^(1-n)) therefore x = 1/3 * (1+10^(1-n)) So, since you're trying to find out what the value of this number is when n is infinity, you find the limit of the function as n approaches infinity. As you can see, if n gets very large, 10^(1-n) gets very small, eventually reaching zero. Therefore, when n is infinite, your equation reduces to this x = 1/3 * (1+0) = 1/3 * 1 = 1/3 Hence why .33~ is equal to 1/3.
Just to add to what I said above, this is ONLY even REMOTELY true when you take the limit of x^x as x approaches 0 from the positive side. However, it's a limit at best, and not an actual value. The fact that it only works from the positiv side makes it an even weaker argument. According to your logic, then division by 0 exists, and any number divided by 0 is equal to infinity.
