In my engineering class right now we're building circuits with protoboards and i'm confused it involves a single pull double throw n/o pb switch before i post the problem, it'd be nice to know if anyone has any experience with protoboards =D thanks much
I've used them. I've only had one of my EE classes, don't know how much help I would be. Mine is actually right behind me... ---------------- Now playing on Winamp: Blodsrit - Ridding A Pest via FoxyTunes
I think I've used those boards before, it's probably what I'm thinking of but with a different name. Anyway post up the problem, I'll see what I can do.
Yay, maybe some help i need to draw a schematic for the following [simple] situation, well simple to some, not to me Problem: You have one light switch at the bottom of a stairwell and another at the top, if in the begging both switches are down then the light in the middle of the stairwell is turned off if you turn the switch at the bottom on (up) the light will turn on, and if you walk to the top of the stairwell and turn the light switch on (up) the light bulb will turn off, now both switches are on and the light is off now if you goto the bottom again and turn the switch off the light will come on again slimmed down: construct a circuit that will allow two switches to control a single light bulb no matter the placement of the bulb or switches needs to be a single pull double throw (if you know what that means) if you need me to elaborate, let me know, this is due in 2 days and i hate how the professor will not help :blink: thanks in advanced if anyone out there can help me, i need a drawn schematic, from the schematic i'll create the circuit myself, if you have time, you could pull out paint and do something, but anything is appreciated
Yeah, single pole double throw means it has 1 input, 2 outputs with either of the outputs being an on or off at 1 single time. Let me have a think.
That seems too simple though I think this is right. Both switches are down (off) so no current can flow through the circuit, therefore light is off. If you turn SW1 up, current flows through the switch and goes through the bulb lighting it. If you flick SW2 up current by-passes the light and flows back around to the supply without lighting the bulb. If you then flick SW2 down it stops current by-passing the bulb and lets it go back through again, lighting it. I'm pretty sure that's right, or it's something very similar.
I could be wrong, I never had an HVAC classes, but wouldn't you want the circuit to more or less be mirrored, as in one resistor per part of the loop, else you'd have a short? again I very well could be wrong. my advice, wikipedia it, or check on the MIT class thingy.
i dont think that would work, because if you move, lets say sw1 to off(down) the circuit would be incomplete and yes, you're correct about the single pull double thrown and i'm not sure xlink, i'll have to keep trying
I think you need 1 in, just in front of the light. Wouldn't need more than 1 because other than the light there are no components to protect.
i believe i just solved my problem, correct me if i am wrong though, also please excuse my horrible excuse for a schematic
Actually I checked yours, it seems wrong, if both switches are off (Down) current will still flow through to the light
ahhh dang that is true, but i can't think of any other way i think of it that the switch at the bottom started with being up and the switch at the top was down making the circuit incomplete, but if you turn one either way then its complete, maybe i can explain this theory to my professor and hope he likes it
