Division is the opposite of multiplication, so 1/3 *3=1. Don't tell me that 1/3 *3 is .9999 repeating, not 1 :huh:
Anything is solvable if you bring in random numbers and letters that you pull out of your ass into the equation. Try solving world hunger using that method.
1 divided by 3 is .333 repeating (still with me?) .333 multiplied by 3 is still .999 repeating. However, if we're working with fractions (which don't have repeating numbers), then it works. One Third multiplied by Three = 1.
So doesn't that prove .999 repeating is equal to 1? Unless you're saying that using decimals has nothing to do with using fractions...
They're kinda incompatible when talking with repeating numbers. Strangely enough, .333 repeating DOESN'T equal 1/3.
.3333 recurring means that the number is infinitely getting closer to 1/3 exactly but not yet, kind of like a limit. As someone said before, the number is eternally getting larger but will never reach it as each additional number will fall just short of 1/3(ie. .3, .33, .333, .3333 etc), therefore the 1/3 equivalent in decimal form is undefined.
That's an old factor used in calculus. Every math scientists know that 0+ (which is 0.99999999999 ...) is considered as 1 in some ways, but not really equal to 1.
You can't reduce a variable once you've used it as it's exact form previously in your process. You'd have to store all your values in exact form (infinite) and perform it throughout. You're reasoning is incorrect.
.999....9.... = 1 And why argue with years and years of mathematical experts proving this when none of you have years of experience in their field? http://en.wikipedia.org/wiki/.9_repeating
under our current mathematics ssytem a recurring number which will eventually approacha value equals that value if that makes any sense. it's like lim x->0 | [sin(x)]/x we all know that sinx/x is undefined at that point, but anyone who's taken an elementary calculus class has that memorized as fact. it's proven by the squeeze theorem.
