Math Question

Can someone explain each step for this derivate y = (2x - 3)

 

derivative is

y` = 2

You just use the power rule.
So 2x is really saying 2x^1
Take that power of 1, and times it by 2. Now where the power used to be, minus 1 from it, so you get 0. 2x^0 is actually 2.

So lets say we have 4x^3
Times 4 by the 3. Then for the power, go 3-1.
So we get 12x^2

 

Sorry m8, wrong question right one is y = (2x - 7) ^ 3

^ 3 = cubed

Sorry >_>

 

Chain Rule:

y' = n([g(x])]^n-1 * d/dx[g(x)]

Thus:

Let u = 2x-7
du/dx (derivative of u)= 2

Therefore: 3(u)^3-1 * du/dx
= 3u^2 *2
=6u^2
But u = 2x-7

therefore y' = 6(2x-7)^2

Hopefully did enough steps for you, 99% of the time it's unnecessary to do it in this many steps.

 

Dang It, I knew it I was absent the day we went over the chain rule, thanks Marforce. And I need all the steps xD, I need to under stand the chain rule

 

NP if you need any more help let me know.

Although typing calc. out is a pain