If you take the square root of any real number squared. It will be the real number. For instance, 9^2=81. 81^1/2 =9. 'nuff said.
On a calculator, you need parenthesis. In itself, -9x-9 is 81. Basic math. The calculator reads "-(9^2)," and as such gives it a negative outcome. However, -9^3 is -729. With a negative number, even exponents give positive outcomes, odd give negatives. To the original poster: I've proved myself to be a math geek enough. Ask your fuxing algebra teacher.
Well, maybe I'm just a loser for being in the stupid IMP program that teaches nothing. They freaking changed our curriculum and held me back (for no good reason) and I FORGOT what I'd learned the previous year, that's how stupid the new stuff is. Which is why I never continued with math this year. It's good for people who don't speak english as a first language, but I know how to read, I know how to do story problem, I DON'T know how to do the equations or what they're for. Sorry, that was just a ridiculous rant. I'm still upset with our school... Thankfully, I'm a senior . Continue on with your geniusness o great ferret
Not the guy I quoted, but one of his quotes. The Square Root of -81, IS infact possible. -81^1/2 would be 9i.
*drools stupidly* IMP confused my already confused mind. I'm gonna give up and just read what ya'll have to say, lol. I think I'm learning more here than I did in a whole year of math. But... what's 9i mean? lol
You would normally learn Bases in a computers class, since that is the only logical place you would need them (base 2 or Binary, base 8 or Octal, base 16 or Hexidecimal.) One thing the base does is tell you how many digits (or letters) you have in your system. For instance, Base 2 has 0 and 1; base 8 has 0,1,2...7; base 10 (decimal) has 0,1,2...9; and hex has 0,1,2...9,A,B...F. I can't really think of a clear cut definition for it, but I'm sure somebody can. I'll give you a steps on how to convert it from Base 10 to Base anything. Number in base 10: 284 base 6: ? Step 1: 284 / 6 = 47 with remainder 2 Step 2: 47 / 6 = 7 with remainder 5 Step 3: 7 / 6 = 1 with remainder 1 Step 4: 1 / 6 = 0 with remainder 1 (note: continue these steps under the dividend = 0.) Put those remainders together and you get: 1152 ... So, the answer in Base 6: 1152 (or in Byte form: 00001152) To kind of scope out how base 6 1152 = base 10 284: 1 1 5 2 6^3 + 6^2 + 6^1 + 6^0 or (6^3)*1 + (6^2)*1 + (6^1)*5 + (6^0)*2 Which in base 10 = 216 + 36 + 30 + 2 Which most definally = 284!!!
Imaginaries are easy. sqr(-8) = 2i(sqr(2)) In dealing with negatives all you have to do is pull out an i. i for imaginary. Go figure. This is basic algebra: Any number squared will be positive.
-x^2 is an imaginary number or w.e but the square root of x^2 IS x because x^2 is x*x which square root takes out the X
(Note: (rt) means square root)It should work out that (rt)x^2 = x. If you work it out using the index rules: that square root of a number is the same as that number to the power of a half, and that (x^n)^m = x^m*n then (rt)x^2 = (x^2)^1/2 = x^1 = x. Additional maths does come in handy ...except for logarithms...