Alegbra 2

Discussion in 'General Discussion' started by RealisticHat, Jan 29, 2006.

  1. RealisticHat

    RealisticHat Well-Known Member

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    I am stumped on this question: Carbon-14, an unstable isotope of carbon which decays exponetially to a more stable form, is used to date animal remains. After 5700 years, onehalf of the orginal amount of carbon-14, by weight, remains. Write an exponetial function with base one half relating the amount N of carbon 14 in the animal remains after t years to the orginal amount A. The right answer gets 12 creds!!
     
  2. Broken

    Broken Well-Known Member

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    Can I ask how old you are? <_<
    So I know when to expect questions like this :)
     
  3. RealisticHat

    RealisticHat Well-Known Member

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    I just turned 15 and i am a freshmen in highschool.
     
  4. illine

    illine Well-Known Member

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    wow! man i hate science i dont mind maths i would help you but i ant that good :P
     
  5. Broken

    Broken Well-Known Member

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    You didn't get asked that at school did you?
     
  6. RealisticHat

    RealisticHat Well-Known Member

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    This is math and no this is a question on my homework that is driving me crazy!




    Merged Post:


    still need some help. Anyone know?
     
  7. Archaeopath

    Archaeopath Well-Known Member

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    My first degree's in archaeology, but that was a looooong time ago. Hope this helps (as best I remember it...it won't let me superscript or subscript here so let me know if you want me to email you a .doc with it on)

    The number of atoms A left after time t to the initial number A0 at time zero by the equation describing exponential decay:

    A = A0 e-λt

    where λ is a constant equal to the reciprocal of the meanlife τ. A term better known in relation to radioactive decay is the half-life, T ½. The half-life is related to the meanlife by

    T ½ = (ln2) τ

    Where ln is the natural logarithm to the base e. Meanlives and therefore half-lives are specific to a particular radioactive atom, and for 14C the best estimate of T ½ is 5730. To determine the radiocarbon age, the equation at the top is often written as

    t = -τ ln(A/A0)
     
  8. RealisticHat

    RealisticHat Well-Known Member

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    wow that looks right. 12 creds are rewarded to you. akso send me the .doc to [email protected]. Thnx a bunch!
     
  9. M0nK3y

    M0nK3y Well-Known Member

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    Uh? WHAT?!
     
  10. bliv

    bliv Well-Known Member

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    omg i read the first line of that question and got confused. :P
     
  11. Archaeopath

    Archaeopath Well-Known Member

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    you're welcome. Email sent.

    and thanks for the creds :)
     

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